Match List-I with List-II. Choose the correct | vedclass

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Question

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \right

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

Vedclass · Answer

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \rightarrow$ Reimer-Tiemann reaction: Phenol reacts with $CHCl_3$ and $NaOH$ followed by $HCl$ to form salicylaldehyde. Matches with $III$.$C \rightarrow$ Oxidation of phenol: Phenol is oxidized by $Na_2Cr_2O_7$ and $H_2SO_4$ to $p$-benzoquinone. Matches with $I$.$D \rightarrow$ Williamson ether synthesis: Phenol reacts with $NaOH$ to form sodium phenoxide,which then reacts with $CH_3Cl$ to form anisole $(PhOCH_3)$. Matches with $II$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

Column-$I$ (Reaction)	Column-$II$ (Condition)
$(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$	$(i)$ $20\% \ H_3PO_4, 358 \ K$
$(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$	(ii) $Cu, 573 \ K$
$(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$	(iii) $85\% \ H_3PO_4, 440 \ K$
$(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$	(iv) $H_2SO_4, 443 \ K$

Column-$I$	Column-$II$	Column-$III$
$(A) \ HO-CH_2-CH_2OH$	$(1) \ \text{sec-Butyl alcohol}$	$(i) \ \text{Ethane-1,2-diol}$
$(B) \ CH_3-CH(OH)-CH_2CH_3$	$(2) \ \text{Isopropyl alcohol}$	$(ii) \ \text{2,2-Dimethylpropan-1-ol}$
$(C) \ CH_3-CH(OH)-CH_3$	$(3) \ \text{Ethylene glycol}$	$(iii) \ \text{Butan-2-ol}$
$(D) \ (CH_3)_3C-CH_2OH$	$(4) \ \text{Neopentyl alcohol}$	$(iv) \ \text{Propan-2-ol}$

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

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